[Twisted-Python] How to send response 401

[Itamar Shtull-Trauring]

On Tue, 10 Jun 2003 08:10:50 -0600
"Justin Johnson" <justinjohnson at fastmail.fm> wrote:

> 	def render(self, request):
> 		headers = request.getAllHeaders()
> 		if headers.has_key("authorization"):
> 			real_auth = '%s:%s' % (config.adminUser,
> 			config.adminPassword) auth = headers["authorization"]
> 			auth = auth.replace("Basic ","")
> 			decoded_auth = decodestring(auth)
> 			if decoded_auth == real_auth:
> 				return xmlrpc.XMLRPC.render(self, request)
> 		else:
> 			self.send_response(401)
> 			self.end_headers()

Note you can do request.getUser() and request.getPassword(), IIRC,
instead of parsing the Basic auth header yourself.