[Twisted-Python] XmlStream and addObserver - root element's name?
Marcin GliĆski
marcin at ascii-art.pl
Wed Dec 17 04:25:10 MST 2008
Hello!
There's a problem I can't find an answer to. I'd like to design Xml
based protocol.
I've found XmlStream, read doc and found addObserver method. I wrote
simple code:
class XmlTest(xmlstream.XmlStream):
# (...)
def connectionMade(self):
xmlstream.XmlStream.connectionMade(self)
self.addObserver("/frame", self.frameHandler)
# (...)
# (...)
def frameHandler(self, data):
print "Wilma, I'm Home!"
When I send XML with frame element as a root:
<frame>
<whatever/>
</frame>
FrameHandler isn't executed, but if I put frame element inside some
other root element:
<sheep>
<frame>
<whatever/>
</frame>
</sheep>
Then my handler is activated. Why? First, I thought maybe my XPath
knowledge is wrong,
so I checked few tutorials[1] and they told me there's something wrong with
addObserver method. How to make it working?
~MG.
(Hi, I'm new here :)
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