[Twisted-Python] integrating a Qt interface with twisted, qt5, python 2.x
Clayton Daley
clayton.daley at gmail.com
Sun Jun 19 09:34:30 MDT 2016
I believe your problem is this line:
> sys.exit(app.exec_())
Two issues:
- It looks like app.exec_() blocks (e.g.
http://stackoverflow.com/questions/22289423/how-to-avoid-qt-app-exec-blocking-main-thread
)
- When it unblocks, the program sys.exit() terminates (
https://docs.python.org/2/library/sys.html#sys.exit)
Thus, your app never reaches any of the twisted code. If you're not
familiar with debugging tools that let you walk through the code, adding a
print line between each line of actual code would have made it obvious that
you never got past this line.
Clayton Daley
On Fri, Jun 17, 2016 at 11:26 AM, steven meier <commercials24 at yahoo.de>
wrote:
> hi,
>
>
> why does the code below print "testing..." but not "123" 5 seconds after
> the application started?
>
>
>
>
> import sys
> from PyQt5 import QtWidgets
> from untitled import Ui_MainWindow
> #from webchat import get_main_page
>
> class Main(QtWidgets.QMainWindow):
>
> def __init__(self):
> QtWidgets.QMainWindow.__init__(self)
> self.ui = Ui_MainWindow()
> self.ui.setupUi(self)
> self.setupSignals()
>
> def button_1_Clicked(self):
> self.ui.textbox_2.setText(self.ui.textbox_1.text())
>
> def setupSignals(self):
> #self.ui.textbox_1.textChanged.connect(self.textbox_1_Changed)
> self.ui.button_1.clicked.connect(self.button_1_Clicked)
>
>
>
>
> if __name__ == '__main__':
> #app = QtWidgets.QApplication(sys.argv)
>
> app = QtWidgets.QApplication(sys.argv) # your code to init QtCore
> import qt5reactor
> qt5reactor.install()
>
> print "testing..."
>
> #get_main_page()
> window = Main()
> window.show()
> sys.exit(app.exec_())
> def printMe(argument):
> print argument
>
> def lala():
> reactor.callLater(5, printMe, '123')
>
>
> lala()
> reactor.run()
>
>
>
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