[Twisted-Python] How to use .rpy do upload ?
Leon
square.erica at msa.hinet.net
Mon Nov 29 02:35:40 MST 2004
<!--upload page-->
<form method="POST" enctype="multipart/form-data" action="test.rpy">
<input type="file" name="filename">
<input type="submit">
</form>
#rpy script
from twisted.web.resource import Resource
class test(Resource):
def render_POST(self,request):
f = open("/root/basic_daemon/htdocs/test/test.txt","wb") #absolute path,the path must use chmod modify authorization
f.write(request.args.get('filename')[0])
f.close()
return "<html><body>" + 'success' + "</body></html>"
resource = test()
----by Leon----
----- Original Message -----
From: Iap, Singuan
To: leon_lee at thecus.com
Sent: Monday, November 29, 2004 4:56 PM
Subject: FW: [Twisted-Python] How to use .rpy do upload ?
If you got answer.
Why not answer yourself onto the post?
singuan
------------------------------------------------------------------------------
From: twisted-python-bounces at twistedmatrix.com [mailto:twisted-python-bounces at twistedmatrix.com] On Behalf Of Leon
Sent: Monday, November 29, 2004 11:43 AM
To: twisted-python at twistedmatrix.com
Subject: [Twisted-Python] How to use .rpy do upload ?
I am a beginner,how can use .rpy do upload ???
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